Python Connector -- returning a dictionary

[mstuy]

Hello!

I want to return a dictionary from the Python connector but I keep getting an error when I do so. Is this possible to do?

[meghan-legaspi · Accepted solution]

Hi @mstuy,

Are you trying to add a user-created library? Here is more documentation on current Python Connector capabilities: https://docs.workato.com/connectors/python.html#usage-inspiration 

If you can provide more info on what recipe you are trying to build, I can have someone from our team reach out.

Cheers,
Meghan

[gary1 · Accepted solution]

"Internal Error" usually means something else is going wrong within your script. I suggest running the script in another IDE to figure it out (better logging and error reporting), or simply start with a simpler script in the Workato action to ensure the basics are correct.

I wrote this simple code to return your intended output and it works perfectly. This suggests your script is crashing elsewhere, or it's not generating the output object the way you expect it to be formatted.

def main(input):
     return {'output': [{"label": ['a', 'b', 'c'], "label2" : ['d', 'e', 'f']}]}

Quick note: I didn't write an output schema for the Python action. This is the default output.

As an alternative, you can use Ruby or Javascript ; )

[meghan-legaspi · Accepted solution]

Hi @mstuy,

Are you trying to add a user-created library? Here is more documentation on current Python Connector capabilities: https://docs.workato.com/connectors/python.html#usage-inspiration 

If you can provide more info on what recipe you are trying to build, I can have someone from our team reach out.

Cheers,
Meghan

[mstuy]

Hello @meghan-legaspi !

I am not trying to add a user-created library. I am passing in two lists of records for the input to the Python connector and then within the connector I am building up a dictionary based on the input records. I am mapping strings to arrays of strings.

Ex: dictionary = {"label": ['a', 'b', 'c'], "label2" : ['d', 'e', 'f']}

The error I am running into is when I try to return the dictionary as the output. After the Python Connector step in the recipe, I would like to iterate over the dictionary key value pairs. Is there a specific way to define the output schema so that this is something I can do?

Thanks,
Meigon

[mstuy]

I am getting an "Internal Error" when I try to run the recipe.

[gary1 · Accepted solution]

"Internal Error" usually means something else is going wrong within your script. I suggest running the script in another IDE to figure it out (better logging and error reporting), or simply start with a simpler script in the Workato action to ensure the basics are correct.

I wrote this simple code to return your intended output and it works perfectly. This suggests your script is crashing elsewhere, or it's not generating the output object the way you expect it to be formatted.

def main(input):
     return {'output': [{"label": ['a', 'b', 'c'], "label2" : ['d', 'e', 'f']}]}

Quick note: I didn't write an output schema for the Python action. This is the default output.

As an alternative, you can use Ruby or Javascript ; )